正则表达式匹配括号(Regex match parenthesis)

正则表达式匹配括号(Regex match parenthesis)

我有以下字符串：

The service(s), foo bar

我有一个正则表达式，检查字符串中是否包含“The”和“service（s）”字样。 我应该用反斜杠转义括号，但它似乎不起作用。 我必须使用这个正则表达式的逻辑结构。 你能帮我解决逃跑问题吗？

不工作：

(^(?=.*\b(?i)The(?-i)\b)(?=.*\b(?i)service\(s\)(?-i)\b).*$)

目标语言是C＃。

I have the following string:

The service(s), foo bar

I have a regex that checks if the words 'The' and 'service(s)' are contained within the string. I'm supposed to escape the brackets with backslash, but it does not seem to work. I must use the logical structure of this Regex. Can you help me fix the escaping?

Not working:

(^(?=.*\b(?i)The(?-i)\b)(?=.*\b(?i)service\(s\)(?-i)\b).*$)

Target language is C#.

最满意答案

service(s)结束括号断言下一个立即位置是非单词边界。 所以你不需要last \b标记，因为你可能意味着一个非字边界\B 我认为您不需要设置和取消设置不区分大小写的修饰符：

(?i)(?=.*\bThe\b)(?=.*\bservice\(s\)\B).*$

Closing parenthesis in service(s) asserts that next immediate position is a non-word boundary. So you don't need last \b token since you possibly meant a non-word boundary \B. I don't think you need to set and unset case-insensitive modifier either:

(?i)(?=.*\bThe\b)(?=.*\bservice\(s\)\B).*$