Python：将减去的unix时间转换为小时/分钟/秒(Python: Convert subtracted unix time into hours/mins/seconds)

Python：将减去的unix时间转换为小时/分钟/秒(Python: Convert subtracted unix time into hours/mins/seconds)

我收到了三种不同的unixtimes

lastSeen = 1416248381 firstSeen = 1416248157

最后一个是lastSeen - firstSeen：

duration = 224

现在，我可以将lastSeen和firstSeen转换成日期时间没有问题。 但我在这段时间里遇到了麻烦。

我不确定如何将持续时间转换为分钟/秒等。 有没有人有任何想法，如果这可以做到？

I have received three different unixtimes

lastSeen = 1416248381 firstSeen = 1416248157

and the last one is lastSeen - firstSeen:

duration = 224

Now, I can convert lastSeen and firstSeen into a datetime no problem. But I am having trouble with the duration.

I am unsure how to convert the duration into something like minutes/seconds. Does anyone have any idea if this can be done?

最满意答案

您需要将秒转换为小时与分钟，并且您可以使用日期时间来完成

import datetime lastSeen = 1416248381 firstSeen = 1416248157 duration = lastSeen - firstSeen str(datetime.timedelta(seconds=duration))

输出将是： '0:03:44' : '0:03:44' : '0:03:44'

没有str()函数，你将得到： datetime.timedelta(0, 224)

---

使用时间

import time time.strftime("%H:%M:%S", time.gmtime(duration))

输出将是： '0:03:44' : '0:03:44' : '0:03:44'

You need to convert your seconds to Hours&Minutes and you can do it using datetime

import datetime lastSeen = 1416248381 firstSeen = 1416248157 duration = lastSeen - firstSeen str(datetime.timedelta(seconds=duration))

The ouput will be: '0:03:44'

Without the str() function you'll have: datetime.timedelta(0, 224)

---

Using time

import time time.strftime("%H:%M:%S", time.gmtime(duration))

The ouput will be: '0:03:44'