删除有空列表的列表(Removing list having empty list)

删除有空列表的列表(Removing list having empty list)

我有以下列表：

a = [[['trial1', 'trial2'], 4], [[], 2]]

我想删除列表中有一个空列表。所以下面的结果：

c = [[['trial1', 'trial2'], 4]]

我正在使用下面的代码：

c = [] for b in a: temp =[x for x in b if x] if len(temp)>1: c.append(temp)

它工作正常，但它似乎不是一个完成此任务的“好方法”。 有没有更优雅的方式？

I have the following list:

a = [[['trial1', 'trial2'], 4], [[], 2]]

and I want to remove the list that have inside an empty list.So the following result:

c = [[['trial1', 'trial2'], 4]]

I am using the following code:

c = [] for b in a: temp =[x for x in b if x] if len(temp)>1: c.append(temp)

It works ok, but it seems not to be a 'good way' of doing this task. Is there a more elegant way?

最满意答案

c = [l for l in a if [] not in l] c = [l for l in a if [] not in l]