你如何“打破”功能？(How do you “break” out of a function?)

你如何“打破”功能？(How do you “break” out of a function?)

给定一个函数返回一个值，是否有可能在给定的条件下退出函数而不返回任何东西？ 如果是这样，你怎么能做到这一点？

例：

int getNumber () { . . . }

所以说你在这个功能。 有没有办法退出它的方法？

Given a function that returns a value, is it possible to exit the function given a certain condition without returning anything? If so, how can you accomplish this?

Example:

int getNumber () { . . . }

So say you are in this function. Is there a way to exit it without it doing anything?

最满意答案

你有两个选择： return或throw 。

int getNumber() { return 3; } int getNumber() { throw string("Some Var"); }

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如果你throw ，你必须catch你扔的类型。

int maint(int argc, char ** argc) { try { getNumber(); } catch(string std) { //Your code will execute here if you throw } }

You have two options: return something or throw.

int getNumber() { return 3; } int getNumber() { throw string("Some Var"); }

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If you throw, you have to catch the type you threw.

int maint(int argc, char ** argc) { try { getNumber(); } catch(string std) { //Your code will execute here if you throw } }