如果目录为空，我怎样才能跳过一个咕噜的任务？(How can I skip a grunt task if a directory is empty)

如果目录为空，我怎样才能跳过一个咕噜的任务？(How can I skip a grunt task if a directory is empty)

我使用grunt-contrib的concat和uglify模块来处理一些javascript。 目前如果src/js/为空，它们仍然会创建一个（空）concat'd文件，以及缩小版本和源地图。

我想要在继续​​之前检测src/js/文件夹是否为空，如果是，则该任务应该跳过（不失败）。 任何想法如何做到这一点？

I'm using grunt-contrib's concat and uglify modules to process some javascript. Currently if src/js/ is empty, they will still create an (empty) concat'd file, along with the minified version and a source map.

I want to task to detect if the src/js/ folder is empty before proceeding, and if it is, then the task should skip (not fail). Any ideas how to do this?

最满意答案

解决方案可能不是最漂亮的，但可以给你一个想法。 您需要首先运行npm install --save-dev glob 。 这是基于你提到的部分Milkshake项目。

grunt.registerTask('build_js', function(){ // get first task's `src` config property and see // if any file matches the glob pattern if (grunt.config('concat').js.src.some(function(src){ return require('glob').sync(src).length; })) { // if so, run the task chain grunt.task.run([ 'trimtrailingspaces:js' , 'concat:js' , 'uglify:yomama' ]); } });

比较的要点： https ： //gist.github.com/kosmotaur/61bff2bc807b28a9fcfa

The solution may not be the prettiest, but could give you an idea. You'll need to run something like npm install --save-dev glob first. This is based on part of the Milkshake project you mentioned.

grunt.registerTask('build_js', function(){ // get first task's `src` config property and see // if any file matches the glob pattern if (grunt.config('concat').js.src.some(function(src){ return require('glob').sync(src).length; })) { // if so, run the task chain grunt.task.run([ 'trimtrailingspaces:js' , 'concat:js' , 'uglify:yomama' ]); } });

A gist for comparison: https://gist.github.com/kosmotaur/61bff2bc807b28a9fcfa